Math
posted by Jake .
Solve (sinx1)(cosx 1/2) = 0 where 0≤x<2pi
a) pi/3, pi/2, 5pi/3
b) pi/6, 5pi/6, pi
c) pi/3, pi, 5pi/3
d) pi/6, pi/2, 5pi/6

sin x = 1 when x = pi/2
cos x = 1/2 when x = pi/3 and pi/3 which is 6 pi/3  pi/3 = 5 pi/3
so
pi/3 , pi/2 , 5 pi/3 a)
and for heavens sake remember that
sin^2 x + cos^2 x = 1 !!!!
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