A closed container with a mixture of hydrogen, helium, and argon has a total pressure of 2.90 atm. The partial pressure of hydrogen is 0.500 atm and the partial pressure of argon is 760. mm Hg. What is the partial pressure of helium?
Ptotal = PH2 + PAr + PHe
One unknown, solve for that.
Note: you will need to convert sole of the units. All must be in the same unit.I would change A to atm si nce everything else is in atm. atm = mm Hg/760 mm Hg.
To find the partial pressure of helium, we need to first convert the pressure of argon from mm Hg to atm since the unit of pressure for hydrogen is atm.
1 atm is equal to 760 mm Hg, so 760 mm Hg is equal to 1 atm.
Now, we can convert the pressure of argon from mm Hg to atm:
Pressure of argon = 760 mm Hg / 760 mm Hg/atm = 1 atm
Now we have the partial pressure of hydrogen and argon in atm:
Partial pressure of hydrogen = 0.500 atm
Partial pressure of argon = 1 atm
To find the partial pressure of helium, we need to subtract the sum of the partial pressures of hydrogen and argon from the total pressure of the container:
Partial pressure of helium = Total pressure - Partial pressure of hydrogen - Partial pressure of argon
Partial pressure of helium = 2.90 atm - 0.500 atm - 1 atm
Partial pressure of helium = 1.40 atm
Therefore, the partial pressure of helium in the container is 1.40 atm.