Please explain how to solve:
A circular table is painted yellow with a red square in the middle. The radius of the tabletop is 6x. The side length of the red square is 3x. What is the area of the yellow part of the tabletop? Write your answer in factored form.
To find the area of the yellow part of the tabletop, we need to subtract the area of the red square from the area of the entire circular table.
The area of a circle can be found using the formula A = πr^2, where A is the area and r is the radius. In this case, the radius is given as 6x.
So, the area of the circular table is A_circle = π(6x)^2 = 36πx^2.
The area of a square is found by multiplying the length of one side by itself. In this case, the side length of the red square is given as 3x.
Therefore, the area of the red square is A_square = (3x)^2 = 9x^2.
To find the area of the yellow part of the tabletop, we subtract the area of the red square from the area of the circular table:
A_yellow = A_circle - A_square
= 36πx^2 - 9x^2
= 9x^2(4π - 1)
So, the area of the yellow part of the tabletop is 9x^2(4π - 1) in factored form.
Formula for area of table minus formula for area of square.
Do you know those two formulas? If not, look in your textbook or Google them.
do i minus them then ?
area of a sqaure is : a^2