Given the G.P 05,0.005,0.0005.find the 7th term,
find the sum of the 1st 7th term
I will assume to meant that first term to be .05
a=.05
r = .1
term(7) = ar^6 = (.05) (.1)^6 = .00000005
(notice term2 had 2 zeros before the 5
term3 had 3 zeros before the 5
..
term7 has 7 zeros before the 5 )
sum(7) = (.05)(1 - .1^7)/(1 - .1)
= .05555...