What products are formed when aqueous solutions of Na2SO4, Fe3SO42, and BaCl2 are mixed together ? Can someone help me write out a balanced equation for the reaction that occurs.
Na2SO4(aq) + BaCl2(aq) ==> BaSO4(s) + 2NaCl(aq)
I don't recognize Fe3(SO4)2. You may mean FeSO4 or Fe2(SO4)3, BaSO4(s) is the end product.
yes I mean Fe2(SO4)3. How come you only used TWO of the reactants for your equation?? What happens with the third one?
BaSO4 is the insoluble material out of all of these. The same thing happens with Fe2(SO4)3.
Fe2(SO4)3(aq) + 3BaCl2(aq) ==> 3BaSO4(s) + 2FeCl3(aq)
Both of these reactions are going on at the same time. It is far easier to make everything balance if we write them separately than try to put them together.
To determine the products formed when aqueous solutions of Na2SO4, Fe3SO42, and BaCl2 are mixed together, we need to find out if any precipitation reactions occur.
First, let's write out the balanced ionic equations for each individual reaction:
Na2SO4(aq) → 2Na+(aq) + SO42-(aq)
Fe3SO42(aq) → 3Fe2+(aq) + 2SO42-(aq)
BaCl2(aq) → Ba2+(aq) + 2Cl-(aq)
Now, to determine the products formed when these solutions are mixed together, we need to examine potential double replacement reactions. This occurs when the positive ions from one compound switch places with the positive ions of another compound.
In this case, the SO42- ion from Na2SO4 can react with either the Ba2+ or Fe2+ ions in the other compounds, resulting in the formation of insoluble precipitates.
So, the possible products are:
Na2SO4(aq) + BaCl2(aq) → BaSO4(s) + 2NaCl(aq)
Na2SO4(aq) + Fe3SO42(aq) → Fe2(SO4)3(s) + 2Na2SO4(aq)
The balanced equation for the reaction between Na2SO4 and BaCl2 is:
2Na2SO4(aq) + BaCl2(aq) → BaSO4(s) + 4NaCl(aq)
And the balanced equation for the reaction between Na2SO4 and Fe3SO42 is:
3Na2SO4(aq) + Fe3SO42(aq) → Fe2(SO4)3(s) + 6Na2SO4(aq)
Therefore, the products formed when aqueous solutions of Na2SO4, Fe3SO42, and BaCl2 are mixed together are BaSO4, NaCl, and Fe2(SO4)3.