How much kinetic energy does a 2000 kg traveling 70 mph have?

A ball with mass m projected horizontally o� the end of a table with an initial kinetic energy K. At a time t after

it leaves the end of the table it has kinetic energy 3K. What is t? Neglect air resistance.

gdeh

To find the kinetic energy of an object, you need to use the formula:

Kinetic Energy (KE) = (1/2) * mass * velocity^2

Given that the mass of the object is 2000 kg (kilograms) and the velocity is 70 mph (miles per hour), we need to convert the velocity to meters per second (m/s) as the SI unit system is commonly used in scientific calculations.

First, let's convert the velocity from mph to m/s:

1 mph = 0.44704 m/s (approximately)

So, at 70 mph, the velocity would be:

70 mph * 0.44704 m/s = 31.2928 m/s (approximately)

Now, we can use the converted value of velocity in the kinetic energy formula:

KE = (1/2) * mass * velocity^2
= (1/2) * 2000 kg * (31.2928 m/s)^2

Calculating further:

KE ≈ (1/2) * 2000 kg * 978.576 m^2/s^2
≈ 978,576 Joules

Therefore, the kinetic energy of a 2000 kg object traveling at 70 mph is approximately 978,576 Joules.