For the reaction Al (s) + 3 HCl (aq) -> AlCl3 (s) + ₃/₂ H2 (g), it was observed
that when 4.00 g of aluminum reacted with excess HCl, exactly 30.0 kJ of heat
were released. The delta H for this reaction is
a) – 91.3 kJ
b) – 120 kJ
c) – 202 kJ
d) – 7.50 kJ
I really need some assistance
The question really is, 30 kJ heat released to react 4.00 g Al, how much heat is released to burn 1 mol (26.98g) Al.
30 kJ x (26.98./4.00) = ?