Post a New Question

Geometry

posted by .

Find the surface area of a sphere with a circumference of 40 ft. Round to the nearest tenth.

  • Geometry -

    since
    C = 2πr, r = C/2π

    V = 4/3 π r^3 = 4/3 π (C/2π)^3 = C^3/6π^2 = 64000/6π^2

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question