The compound copper(II) nitrate is a strong electrolyte. Write the reaction when copper(II) nitrate is put into water
The complex you get is the copper (II) hexaquo complex.
Cu(NO3)2+6H2O⟶Cu(H2O)^+2(6) +2NO3^-
To determine the reaction when copper(II) nitrate (Cu(NO3)2) is dissolved in water, we need to understand that ionic compounds dissociate into their constituent ions when dissolved in water. The positive and negative ions become surrounded by water molecules, forming a solution.
The formula unit for copper(II) nitrate is Cu(NO3)2, which indicates that it contains one copper ion (Cu2+) and two nitrate ions (NO3-) in its crystal lattice. When this compound is placed in water, it dissociates into its constituent ions:
Cu(NO3)2(s) → Cu2+(aq) + 2NO3-(aq)
In the dissociation, the solid copper(II) nitrate breaks apart into aqueous copper ions, Cu2+(aq), and aqueous nitrate ions, NO3-(aq). These ions freely move in the solution and are responsible for the compound's ability to conduct electricity, making copper(II) nitrate a strong electrolyte.