chemistry

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How much aluminum nitrate can be found
when 12 g of aluminum react with lead(II)
nitrate?
Answer in units of mol

  • chemistry -

    2Al + 3Pb(NO3)2 ==> 2Al(NO3)3 + 3Pb
    1. Convert 12 g Al to moles. moles = g/molar mass
    2. Using the coefficients in the balanced equation, convert mol Al to moles Al(NO3)3
    3. Convert moles Al(NO3)3 to g. g = moles x molar mass.

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