Math 543
posted by lily .
The number 3136 is the sum of the first how many odd whole numbers?

Math 543 
Mario
56

Math 543 
claudia
how did you solve

Math 543 
Reiny
so we have
1+3+5+7+... = 3136
let the number of terms of this AS be n
(n/2)(2a +(n1)d) = Sum(n)
So we have a=1, d=2 , and n = ?
(n/2)(2 + (n1)2) = 3136
times 2 ....
n(2 + 2n  2) = 6272
2n^2 = 6272
n^2 = 3136
n = ± 56 , but n has to be a positive whole number,
there are 56 terms
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