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Precalculus

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A geometric series has t1 = 3 and r = 2. If tn = 96. What does n equal in this problem?

What is the special name given to the terms between 3 and 96 in this problem?

  • Precalculus -

    You are given that a = 3 and r = 2
    so
    tn = ar^(n-1)
    96 = 3(2^(n-1)
    32 = 2^(n-1)
    2^5 = 2^(n-1)
    n-1 = 5
    n = 6

    3, 6, 12, 24, 48, 96
    terms in between are called geometric means

  • Precalculus -

    Thanks!

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