physics
posted by Jason .
A ball is thrown from a cliff upward with a speed of 21 m/s and at an angle of 56 degrees to the horizontal. How high does it go above the cliff to the nearest tenth of a meter?

physics 
drwls
Initial vertical velocity component = Voy = 21 sin 56 = 17.41 m/s
Voy^2 = 2 g H
Solve for H
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