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A ball is thrown from a cliff upward with a speed of 21 m/s and at an angle of 56 degrees to the horizontal. How high does it go above the cliff to the nearest tenth of a meter?

  • physics -

    Initial vertical velocity component = Voy = 21 sin 56 = 17.41 m/s

    Voy^2 = 2 g H

    Solve for H

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