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An 80 kg person decides to jump off the back end of a 30 kg canoe. His friend measures the speed of the canoe after he jumps to be 0.8 m/s. The canoe was initially at rest. What rule would I use to find the speed of the person who jumped?

  • Science -

    initially there was 0 momentum. That momentum is conserved. So, assigning the canoe's direction as negative,

    30*(-.8) + 80*v = 0
    80v = 24
    v = +.3m/s

  • Science -

    conservation of momentum

    initial mometum= final momentum
    (80+30)Vc=30*.8-80*V

    but Vc=0, the canoe was not moving initially. Solve for V

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