In December of 1989, a KLM Boeing 747 airplane carrying 231 passengers entered a cloud of ejecta from an Alaskan volcanic eruption. All four engines went out, and the plane fell from 27800 ft to 13700 ft before the engines could be restarted. It then landed safely.

how long did it fall before the engines were restarted????

fell 14,100 ft

14100 = (1/2)g t^2
in English units g = 33.2 ft/s^2
28200 = 32.2 t^2
t =29.6 seconds or half a minute

g = 32.2 ft/s^2

it needs to be v= ? mph for the answer.....how long did it fall before the engines were restarted

LOL Amy, you asked how long it fell. That is not a speed in mph.

If you ask how fast it was falling after 29.6 seconds, that is another question.
v = g t = 32.2 (29.6)
then convert ft/s to m/hr

32.2(29.6)= 10.830mph would that be the anwser

scratch that 32.2(29.6)= 953.12 ft/s and converting that would be 649.859 ok would that be the anwser lol

32.2*29.6 = 953 ft/s

953 ft/s * 3600 s/hr * 1 mi/5280 ft = 650 mph

That is correct but is surely not what happened because the plane in fact would have glided down slowly with major aerodynamic lift from the wings.

thank you for the help :)

You are welcome.

To determine how long the KLM Boeing 747 airplane fell before the engines were restarted, we need to calculate the time it took for the descent from 27,800 feet to 13,700 feet. We can do this by using the formula for time in freefall, assuming no other forces are acting on the plane during its descent.

First, let's find the distance covered during the descent. The difference in altitude is:

27,800 ft - 13,700 ft = 14,100 ft

Now, we need to convert this distance into the corresponding SI unit, meters:

14,100 ft * 0.3048 m/ft = 4,297.08 meters

Next, we can use the formula for freefall distance with constant acceleration:

d = (1/2) * g * t^2

Where:
d = distance
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time

Rearranging the formula, we can solve for time:

t = √(2 * d / g)

Plugging in the values:

t = √(2 * 4,297.08 m / 9.8 m/s^2)
t ≈ √(875.56 s^2) ≈ 29.589 seconds

Therefore, the KLM Boeing 747 airplane fell for approximately 29.589 seconds before the engines were restarted.