A tank was filled with 20L of water. However, there was a hole and 2/3L was leaked out every minute.How long did it take for the tank to become empty?
FIRST,look for the unit
L----Litre
leak?L per minute-------L m^-1
that mean
L/ L m^-1
=1/ m^-1
=m
therefore,
ans:
20/(2/3)
=30minutes.
yup, that's what i got, thanks for verifying
To find out how long it took for the tank to become empty, we need to determine the rate at which water was being leaked and use that to calculate the total time.
Given information:
- Initial amount of water in the tank = 20 liters.
- Amount of water leaked per minute = 2/3 liters.
To find the time it took for the tank to become empty, we can set up an equation:
Total time = Remaining water / Rate of leakage
Since the tank will be empty when there is no remaining water, the equation becomes:
Total time = 0 / Rate of leakage
The rate of leakage is given as 2/3 liters per minute.
So, substituting the values into the equation:
Total time = 0 / (2/3)
Total time = 0
Therefore, the total time it took for the tank to become empty is 0 minutes.