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chemistry student weighs out 0.123 grams of chloroacetic acid (HCH2ClCO2) into a 250. milliliter volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1200 moles/liter NaOH solution.

Calculate the volume of NaOH solution the student will need to add to reach the equivalence point.

  • Chemistry -

    moles chloroacetic acid = M x L
    moles acid = moles NaOH
    M NaOH = moles NaOH/L NaOH. You have M NaOH and M NaOH, solve for L NaOH and convert to mL if you wish.

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