trig
posted by Claire .
I don't know to find the derivative of the following trig functions. Please help.
f(x)= cotx
h(x)= secx
i(x)= cscx

any calculus text will list the trig functions and their derivatives.
Respond to this Question
Similar Questions

trig
express this in sinx (1/ cscx + cotx )+ (1/cscx cotx) i got 2sinx is that right? 
Trig
Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (x=theta BTW) 
drwls
My previous question: Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) = (sinx/cosx)*cotx*(1/sinx) "The last steps should be obvious" Not to me. I can convert (sinx/cosx) to … 
AP calculus BC
hello i know that deriv(cscx) = cscxcotx and that deriv(cos) = sinx deriv(cotx) = ((cscx)^2) my question is: is this (statements below) correct? 
trig
Find a numerical value of one trigonometric function of x if secxcotx=4 A.cscx=1/4 b.secx=4 c.secx=1/4 d.cscx=4 
trig
I don't know to find the derivative of the following trig functions. Please help. f(x)= cotx h(x0= secx i(x)= cscx 
Trig
prove (cscxsecx/cscx+secx)=(cotx1/cotx+1) 
Trig
verify the following identity: tanx+cotx/cscx=secx 
trig proofs
cotx+tanx=secx+cscx 
Precalculus/Trig
I can't seem to prove these trig identities and would really appreciate help: 1. cosx + 1/sin^3x = cscx/1  cosx I changed the 1: cosx/sin^3x + sin^3x/sin^3x = cscx/1cosx Simplified: cosx + sin^3x/sin^3x = cscx/1cosx I don't know …