# trig

posted by Claire

f(x)= cotx

h(x0= secx

i(x)= cscx

## Similar Questions

1. ### trig

express this in sinx (1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is that right?
2. ### Trig

Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (x=theta BTW)
3. ### drwls

My previous question: Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) = (sinx/cosx)*cotx*(1/sinx) "The last steps should be obvious" Not to me. I can convert (sinx/cosx) to …
4. ### AP calculus BC

hello i know that deriv(cscx) = -cscxcotx and that deriv(cos) = -sinx deriv(cotx) = -((cscx)^2) my question is: is this (statements below) correct?
5. ### trig

Find a numerical value of one trigonometric function of x if secxcotx=4 A.cscx=1/4 b.secx=4 c.secx=1/4 d.cscx=4
6. ### trig

I don't know to find the derivative of the following trig functions. Please help. f(x)= cotx h(x)= secx i(x)= cscx
7. ### Trig

prove (cscx-secx/cscx+secx)=(cotx-1/cotx+1)
8. ### Trig

verify the following identity: tanx+cotx/cscx=secx
9. ### trig proofs

cotx+tanx=secx+cscx
10. ### Precalculus/Trig

I can't seem to prove these trig identities and would really appreciate help: 1. cosx + 1/sin^3x = cscx/1 - cosx I changed the 1: cosx/sin^3x + sin^3x/sin^3x = cscx/1-cosx Simplified: cosx + sin^3x/sin^3x = cscx/1-cosx I don't know …

More Similar Questions