math-calculus

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solve equation |x^2-2x-6| using quadratic formula. i not get how to do this and it says quadratic formula.

  • math-calculus -

    you cannot solve it since you cant square root a negative number... unless -2x was positive 2x.

  • math-calculus -

    sorry i missing part of question whole question be |x^2-2x-6| = 4. and answer have to be 1+-sqrt3, 1+-sqrt11 i just not get how to get this.

  • math-calculus -

    f(x) = x^2 - 2x - 6 has roots 1±√7 = -1.65,3.65

    Between the roots, f(x) < 0 and we have
    -(x^2-2x-6) = 4
    x^2 - 2x - 2 = 0
    x = 1±√3
    both those values are in the interval, so they're ok as solutions

    Outside that interval,
    x^2-2x-6 = 4
    x^2 - 2x - 10 = 0
    x = 1±√11

    both those values are outside the interval, so they're ok as solutions

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