chem

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calculate the PH of [OH-]
= 4.5×10−3 M

Please show how you work this problem.

  • chem -

    pOH = -log(OH^-)
    pOH = -log(4.5E-3)
    Then pH + pOH = pKw = 14 so
    pH = 14-pOH
    You should end up with 11.65

  • chem -

    thank you

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