you have 100.0-mL graduated cylinder containing 50.0 mL of water. you drop a 124-g piece of brass (density =8.56 g/cm^3) into water. to what height does the water rise in the graduated cylinder

Question

you have 100.0-mL graduated cylinder containing 50.0 mL of water. you drop a 124-g piece of brass (density =8.56 g/cm^3) into water. to what height does the water rise in the graduated cylinder

Answer 1

mass = volume x density

124g = volume x 8.56
V = ?
The brass will displace its volume so the water will rise from 50.0 mL to 50.0+ V.

Answer 2

so whats the V

Answer 3

we are looking for =cm^3

Answer 4

I substituted the numbers into mass = volume x density. All you need to do is to solve for volume (in mL which is the same as cc).

Answer 5

To find the height to which the water rises in the graduated cylinder, we need to calculate the displacement of water caused by the brass piece when it is immersed in the cylinder. Here's how you can do that:

Step 1: Determine the volume of the brass piece
Using the density and the mass of the brass piece, we can calculate its volume by dividing the mass by the density:
Volume = Mass / Density = 124 g / 8.56 g/cm^3 = 14.45 cm^3

Step 2: Calculate the change in water volume
The change in water volume is equal to the volume of the brass piece since it displaces an equal amount of water. So, the change in volume is 14.45 cm^3.

Step 3: Convert the change in volume to a change in height
Since we know the initial volume of water in the graduated cylinder is 50.0 mL, which is equivalent to 50.0 cm^3, we can calculate the change in height using the formula:
Change in Height = Change in Volume / Base Area

The base area can be calculated using the formula for the area of a circle:
Base Area = π * (cylinder radius)^2

Since the graduated cylinder has a constant diameter, we can assume its radius remains the same throughout our calculations.

Step 4: Calculate the final height of the water
Final Height = Initial Height + Change in Height

Let's calculate:

Assuming the radius of the graduated cylinder remains constant at 1 cm (since the diameter is not provided):

Step 1: Volume of the brass piece = 14.45 cm^3
Step 2: Change in volume = 14.45 cm^3
Step 3: Base Area = π * (1 cm)^2 = π cm^2

Change in Height = (Change in Volume) / (Base Area) = (14.45 cm^3) / (π cm^2) ≈ 4.6 cm

Step 4: Final Height = Initial Height + Change in Height = 50.0 cm + 4.6 cm ≈ 54.6 cm

Therefore, the water will rise to approximately 54.6 cm in the graduated cylinder.

Answer 6

you have 100.0-mL graduated cylinder containing 50.0 mL of water. you drop a 124-g piece of brass (density =8.56 g/cm^3) into water. to what height does the water rise in the graduated cylinder

mass = volume x density

so whats the V

we are looking for =cm^3

I substituted the numbers into mass = volume x density. All you need to do is to solve for volume (in mL which is the same as cc).

Yes.

To find the height to which the water rises in the graduated cylinder, we need to calculate the displacement of water caused by the brass piece when it is immersed in the cylinder. Here's how you can do that:

so now would i do this 124g/8.56 and whatever i get i add it to 50.0