algebra

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a two part canoe trip,the first part of the trip the canoist traveled 58 miles.Second part of the trip he traveled 18 miles at 5mph slower.the total time for trip was 4 hours.What was the speed of both parts of the trip?

  • algebra -

    faster speed --- x mph
    slower speed ---- x-5 mph

    time at slower speed = 58/x
    time at faster speed = 18/(x-5)
    58/x + 18/(x-5) = 4
    times x(x-5)

    58(x-5) + 18x = 4x(x-5)
    58x - 290 + 18x = 4x^2 - 20x
    4x^2 -96x + 290 = 0
    2x^2 - 48x + 145 = 0

    x = (48 ± √1144)/4
    = appr. 20.45 mph or 3.544 mph

    if x = 20.45 , then x-5 = 15.45 mph
    if x = 3.544 mph , then x-5 is a negative, so NO GOOD

    Ridiculous answer!
    I have done my share of canoeing, there is no way you can paddle a canoe at 20 mph!!!!
    Absurd to canoe 76 miles in 4 hours.

  • algebra -

    Thanks

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