algebra
posted by becca .
a two part canoe trip,the first part of the trip the canoist traveled 58 miles.Second part of the trip he traveled 18 miles at 5mph slower.the total time for trip was 4 hours.What was the speed of both parts of the trip?

faster speed  x mph
slower speed  x5 mph
time at slower speed = 58/x
time at faster speed = 18/(x5)
58/x + 18/(x5) = 4
times x(x5)
58(x5) + 18x = 4x(x5)
58x  290 + 18x = 4x^2  20x
4x^2 96x + 290 = 0
2x^2  48x + 145 = 0
x = (48 ± √1144)/4
= appr. 20.45 mph or 3.544 mph
if x = 20.45 , then x5 = 15.45 mph
if x = 3.544 mph , then x5 is a negative, so NO GOOD
Ridiculous answer!
I have done my share of canoeing, there is no way you can paddle a canoe at 20 mph!!!!
Absurd to canoe 76 miles in 4 hours. 
Thanks