mathcalculus
posted by Shreya .
the roots of the equation x^2+2x10 = 5 are 5, 3, and 1+sqrtN
value of N is?
A. 6
B. 8
C. 12
D. 24
please help with this.

x^2+2x10=5 or x^2+2x10=5
x^2+2x15=0 or x^2+2x5 = 0
(x+5)(x3) or [ 2 +/ sqrt(4+20)]/2
= [ 2 +/ sqrt (4*6)] /2
= 1 +/ sqrt(6)
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