Determine the specific heat of iron if 6.1 J of energy are needed to warm 1.50 g of iron from 20 degrees C to 29 degrees C
0.45 J/g*C
q = mass x specific heat x delta T.
6.1 = 1.50g x specific heat x 9
Solve for specific heat.
Sure, let me put on my clown hat and calculate some fun for you!
To determine the specific heat of iron, we can use the formula:
Q = m * c * ΔT
Where:
Q is the heat energy transferred,
m is the mass of the substance,
c is the specific heat capacity, and
ΔT is the change in temperature.
Here's how we can use this formula to solve your problem:
Given:
Q = 6.1 J
m = 1.50 g
ΔT = 29°C - 20°C = 9°C
Now, let's plug in the values:
6.1 J = (1.50 g) * c * 9°C
Dividing both sides by (1.50 g * 9°C):
c = 6.1 J / (1.50 g * 9°C)
Now, let's calculate this:
c ≈ 0.45 J/g°C
So, the specific heat of iron is approximately 0.45 J/g°C. And remember, always keep it cool, just like iron!
To determine the specific heat of iron, we can use the formula:
q = m * c * ΔT
Where:
q is the heat energy (in J),
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in J/g·°C), and
ΔT is the change in temperature (in °C).
We are given:
q = 6.1 J,
m = 1.50 g,
ΔT = 29 °C - 20 °C = 9 °C
Plugging these values into the formula, we have:
6.1 J = 1.50 g * c * 9 °C
Solving for c:
c = 6.1 J / (1.50 g * 9 °C)
c = 6.1 J / 13.5 g·°C
c ≈ 0.45 J/g·°C
Therefore, the specific heat of iron is approximately 0.45 J/g·°C.
To determine the specific heat of iron, you need to use the formula:
q = m * c * ΔT
where:
q is the amount of heat energy transferred,
m is the mass of the substance,
c is the specific heat capacity of the substance, and
ΔT is the change in temperature.
Given information:
q = 6.1 J
m = 1.50 g
ΔT = (final temperature - initial temperature) = (29 degrees C - 20 degrees C) = 9 degrees C
Now, we need to rearrange the formula to solve for c:
c = q / (m * ΔT)
Substituting the given values:
c = 6.1 J / (1.50 g * 9 degrees C)
Before we proceed to calculate, note that specific heat capacity is typically expressed in J/(g°C). To match the units, we need to convert grams to kilograms by dividing the mass by 1000:
c = 6.1 J / (0.00150 kg * 9 degrees C)
Now, calculate the specific heat:
c = 6.1 J / 0.0135 kg°C
After performing the division:
c ≈ 451.85 J/(kg°C)
Therefore, the specific heat of iron is approximately 451.85 J/(kg°C).