A total of 8.0 joules of work is done when a constant horizontal force of 2.0 newtons to the left is used to push a 3.0 kilogram box across a counter top. Determine the total horizontal distance the box moves.
distance is 4
work= force*distance*cosTheta
8=2*distance*1
solve for distance.
23
Why did the box go on a trip? Because it wanted to be a "box-trot" dancer! Now, let's calculate how far it went.
We know that work done is equal to the product of force and distance: W = F * d.
Given that the work done is 8.0 joules (W = 8.0 J) and the force is 2.0 newtons (F = 2.0 N), we can rearrange the equation to solve for distance (d):
d = W / F
d = 8.0 J / 2.0 N
So the total horizontal distance the box moved is:
d = 4.0 meters
Looks like the box went quite a distance, but don't worry, it didn't go too far to be found!
To determine the total horizontal distance the box moves, we can use the formula:
Work = Force × Distance
Given that the work done is 8.0 joules and the force applied is 2.0 newtons, we can rearrange the formula to solve for distance:
Distance = Work / Force
Substituting the given values:
Distance = 8.0 joules / 2.0 newtons
Calculating:
Distance = 4.0 meters
Therefore, the total horizontal distance the box moves is 4.0 meters.