precalc
posted by 95 .
Write the equation of the ellipse in standard form: 4x^29y^240x+36y+100=0

That is not an ellipse. You cannot have x^2 and y^2 terms of opposite sign, for an ellipse.
You have a hyperbola. Complete the squares for standard form. 
okay, Thank you very much:)

wait, I still end up with the wrong answer. I end up with
4(x5)^2/120  9(y+2)^2=120
9 can't go into 120
My procedure:
(4x^240x)(9y^2+36y)=100
4(x^210x +4)9(y^2 +4 +4)=100+ 4(4)9(4)
4(x5)^29(y+2)^2=120
(x5)^2/30  ? 9 can't go into 120 evenly
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4x^29y^240x+36y+100=0 I still end up with the wrong answer. I end up with 4(x5)^2/120  9(y+2)^2=120 9 can't go into 120 My procedure: (4x^240x)(9y^2+36y)=100 4(x^210x +4)9(y^2 +4 +4)=100+ 4(4)9(4) 4(x5)^29(y+2)^2=120 … 
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