geometry
posted by Anonymous .
if angle FGH is similar to angle PQR, FG = 6, PQ = 10, and the perimeter of angle PQR IS 35, find the perimeter of angle FGH

substituting "triangle" for "angle" everywhere,
since FG/PQ = 6/10
p(FGH) = 6/10 * p(PQR) = 6/10 * 35 = 21
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