The electric field intensity between two charged plates is 1.2 103 N/C. The plates are 0.030 m apart. What is the electric potential difference, in volts, between the plates?
E * d = V
1.2*10^3 * .03 = V
To find the electric potential difference (V) between two plates, you can use the formula:
V = Ed
Where E is the electric field intensity and d is the distance between the plates.
Given that the electric field intensity is 1.2 * 10^3 N/C and the distance between the plates is 0.030 m, we can substitute these values into the formula to find the potential difference.
V = (1.2 * 10^3 N/C) * (0.030 m)
V = 36 V
Therefore, the electric potential difference between the plates is 36 volts.
To find the electric potential difference between the plates, you can use the formula:
V = Ed
Where:
V is the electric potential difference (in volts)
E is the electric field intensity (in N/C)
d is the distance between the plates (in meters)
In this case, the value of the electric field intensity (E) is given as 1.2 * 10^3 N/C, and the distance between the plates (d) is given as 0.030 m.
Substituting these values into the formula, we get:
V = (1.2 * 10^3 N/C) * (0.030 m)
Now, let's calculate the electric potential difference:
V = 36 volts
Therefore, the electric potential difference between the plates is 36 volts.