Please help! it has to do with momentum

A 70 k/g woman and her 35 k/g son are standing at rest on an ice rink. They push against each other for .60 s, causing them to glide apart. The speed of the woman immediately after they separate is .55 m/s
question asks what is the magnitude of the total momentum of the 2 people after they push?

zero

No computation is necessary
There are no external forces on the two person system.
Therefore the total momentum does not change, First Law.

Please help! it has to do with momentum

A 70 k/g woman and her 35 k/g son are standing at rest on an ice rink. They push against each other for .60 s, causing them to glide apart. The speed of the woman immediately after they separate is .55 m/s
question asks what is the womans momentum after the push

To find the magnitude of the total momentum of the two people after they push, we need to calculate the individual momenta of the woman and her son, and then add them together.

The momentum of an object can be calculated using the formula:
momentum = mass x velocity

For the woman:
mass = 70 kg (given)
velocity = 0.55 m/s (given)

The momentum of the woman can be calculated as:
momentum_woman = mass_woman x velocity_woman
= 70 kg x 0.55 m/s

For the son:
mass = 35 kg (given)
velocity = -0.55 m/s since they move in opposite directions (magnitude of the velocity will be the same, but the direction will be opposite)

The momentum of the son can be calculated as:
momentum_son = mass_son x velocity_son
= 35 kg x (-0.55 m/s)

Now, we can find the total momentum by adding the individual momenta together:
total_momentum = momentum_woman + momentum_son

Substituting the given values:
total_momentum = (70 kg x 0.55 m/s) + (35 kg x (-0.55 m/s))

Simplifying this equation will give the magnitude of the total momentum of the two people after they push.