a ball of mass 1oog falls from a height of 5m onto a floor and rebounds to a height of 3m . what energy is lost as a result of the impact on the floor ?
m g H1 - m g H2 = m g (5-3) = 2 m g
= 2 (mass in kg, I cam not sure what you typed)(9.81)
2j
To determine the energy lost as a result of the impact on the floor, we need to consider the change in potential energy of the ball.
The potential energy of an object near the Earth's surface is given by the equation: PE = mgh, where m is the mass of the object, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height.
First, let's calculate the potential energy of the ball at its initial height of 5m:
PE_initial = m * g * h_initial = 0.1 kg * 9.8 m/s^2 * 5m = 4.9 J
Next, let's calculate the potential energy of the ball at its rebound height of 3m:
PE_final = m * g * h_final = 0.1 kg * 9.8 m/s^2 * 3m = 2.94 J
The difference in potential energy before and after the impact is the energy lost:
Energy lost = PE_initial - PE_final = 4.9 J - 2.94 J = 1.96 J
Therefore, the energy lost as a result of the impact on the floor is 1.96 Joules.