geometry
posted by Anonymous .
Isosceles triangle ABC has vertices at A(0, 0), B(8, 0), and C(x, 12). The value of x could be

I guess AC = BC
d^2 = x^2 + 144 = (x8)^2 + 144
x^2 16 x + 64 = x^2
x = 64/16 = 4
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