Daniel tosses a ball upwards with an initial velocity of 10.0 m/s. In meters/second, what is the velocity of the ball 1.3 seconds after he threw it? (use 10.0 m/s2 for g and use the upward direction as positive)
Tr = (Vf-Vo)/g = (0-10)/-10 = 1.0 s =
Rise time or time to reach max. height.
Therefore, the ball is falling at 1.3 s.
Vf = Vo + gt = 0 + 10*(1.3-1)=3.0 m/s.