a comet experiences uniform acceleration from 60 m/s to 183 m/s in 10.0 s. what is its rate of acceleration ?

If the motion is in a straight line, divide the speed change by the time interval. If not, more information is required.

An object can accelerate without changing its speed. That is what happens with circular orbits.

6.0m/s^2

12.3m/s/s

To calculate the rate of acceleration of the comet, we can use the formula:

Acceleration (a) = (Final Velocity (v) - Initial Velocity (u)) / Time (t)

Given:
Initial Velocity (u) = 60 m/s
Final Velocity (v) = 183 m/s
Time (t) = 10.0 s

Now, let's substitute the values in the formula:

Acceleration (a) = (183 m/s - 60 m/s) / 10.0 s

Simplifying the equation:

Acceleration (a) = 123 m/s / 10.0 s

Finally, dividing 123 m/s by 10.0 s, we get:

Acceleration (a) = 12.3 m/s²

Therefore, the rate of acceleration of the comet is 12.3 m/s².