Precalculus

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Is this correct?

1. Find the solution set for x^2/(x+3) < 9/(x+3).

x^2/(x+3) < 9/(x+3)

x^2 < 9
x^2 - 9 < 0

(x-3)(x+3)<0

• Precalculus -

x ^ 2 / ( x + 3 ) < 9 /( x + 3 ) Multiply both sides with ( x + 3 )

x ^ 2 < 9

x < + OR - 3

For :

x = - 3

x + 3 = 0

and

x ^ 2 / ( x + 3 ) = infinity

For that reason solution is x < 3

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