Precalculus
posted by Anon .
Is this correct?
1. Find the solution set for x^2/(x+3) < 9/(x+3).
x^2/(x+3) < 9/(x+3)
x^2 < 9
x^2  9 < 0
(x3)(x+3)<0

x ^ 2 / ( x + 3 ) < 9 /( x + 3 ) Multiply both sides with ( x + 3 )
x ^ 2 < 9
x < + OR  3
For :
x =  3
x + 3 = 0
and
x ^ 2 / ( x + 3 ) = infinity
For that reason solution is x < 3
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