# physics

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A 1.4-kg block slides across a rough surface such that it slows down with an accerleration of 1.2 m/s2. What is the coefficient of kinetic friction between the block and the surface?

• physics -

Wb = mg = 1.4 kg * 9.8 N./kg = 13.72 N.
= Weight of block.

Fb = 13.72 N. @ 0 Deg.
Fp = 13.72*sin(0) = 0 = Force parallel to surface.
Fv = 13.72*cos(0) = 13.72 = Force perpendicular to surface.

Fn = Fp-Fk = ma,
0-u*13.72 = 1.4*(-1.2 = -1.68,
-13.72u = -1.68,
u = 0.1224.

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