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A 1.4-kg block slides across a rough surface such that it slows down with an accerleration of 1.2 m/s2. What is the coefficient of kinetic friction between the block and the surface?

  • physics -

    Wb = mg = 1.4 kg * 9.8 N./kg = 13.72 N.
    = Weight of block.

    Fb = 13.72 N. @ 0 Deg.
    Fp = 13.72*sin(0) = 0 = Force parallel to surface.
    Fv = 13.72*cos(0) = 13.72 = Force perpendicular to surface.

    Fn = Fp-Fk = ma,
    0-u*13.72 = 1.4*(-1.2 = -1.68,
    -13.72u = -1.68,
    u = 0.1224.

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