calculus
posted by scarlette. . .need help asap .
find the sum of p+m if the function
g(x)= p(x^2m)/(x+2)(x+5)has a horizontal asymptote at y=5 and a hole at x=2

we know that at large x,
g(x) =~ 5, so p = 5, giving us
g(x) = 5(x^2  m)/(x+2)(x+5)
A hole at x = 2 means that the numerator is divisible by (x+2) so that
g(x) = 5(x+2)(x2)/(x+2)(x+5)
making m = 4
p+m = 9
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