Sue's average for 9 games of bowling is 108. What is the lowest score she can receive for the tenth game to have an average of 110.

Total of 9 games with an average of 108 = 972

so ...
(972+x)/10 = 110
972 + x = 1100
x = 1100-972 = 128

To find the lowest score Sue can receive for the tenth game to have an average of 110, we need to calculate the total score she currently has for the first nine games.

Her average for 9 games is given as 108, so the total score for the first nine games is:

Total score = Average * Number of Games
Total score = 108 * 9
Total score = 972

To have an average of 110 after 10 games, her total score needs to be:

Total score = Average * Number of Games
Total score = 110 * 10
Total score = 1100

To find the lowest score she can receive in the tenth game, we subtract her current total score from the desired total score:

Lowest score for tenth game = Desired total score - Current total score
Lowest score for tenth game = 1100 - 972
Lowest score for tenth game = 128

Therefore, Sue's lowest score for the tenth game to have an average of 110 is 128.

To find the lowest score Sue can receive for the tenth game and still maintain an average of 110, we can start by finding the total score Sue would need to have after ten games.

Sue's average for nine games of bowling is 108, which means the total score for those nine games is (9 * 108) = 972.

To have an average of 110 after ten games, Sue's total score after ten games should be (10 * 110) = 1100.

Now, we can calculate the lowest score Sue can receive for the tenth game by subtracting her total score after nine games from her desired total score after ten games:

1100 - 972 = 128

Therefore, the lowest score Sue can receive for the tenth game and still have an average of 110 is 128.