precalculus
posted by Sara .
solve the following equation show all work log4(x4)= 1.

precalculus 
Reiny
by definition:
log_{4} (x4) = 1
is equivalent to
x4 = 4^1
x4 = 1/4
x = 1/4  4
= 15/4
so we would have log (3/44)
but we cannot take the log of a negative, so ....
no solution. 
precalculus 
Steve
log takes on all real values for its range. So, something's wrong here.
x  4 = 1/4
x = 1/4 + 4
x = 17/4
log_{4}(17/4  4) = log_{4}(1/4) = 1
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