precalculus
posted by Sara .
given the function y=2log(x) find domain, determine vertical asymptote and show work.

log is only defined for positive numbers. So,
domain is x > 0
You know what y = log(x) looks like. Vertical asymptote at x=0.
y = log(x) is just log(x) reflected about the xaxis. Still has the vertical asymptote at x=0.
y = 2  log(x) = log(x) + 2 is just that graph shifted up 2 units. Asymptote does not change.
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