posted by ellah .
A bullet is fired horizontally with a velocity of 250 m/s from the top of a building 100m high. Find the Horizontal and vertical velocities of the bullet when it reaches the ground, the resultant velocity, the horizontal displacement, the net displacement, the direction of the net displacement.
horizontal velocity remains constant throughout the flight. There is no horizontal force or acceleration. So 250 m/s at top and at ground
Now the vertical problem, which is simply falling from 100 meters
-100 = 0 + 0 t - 4.9 t^2
t = 4.52 seconds to fall
down speed at ground = -9.8 t = -44.3 m/s
so speed at ground is 250 horizontal and - 44.3 vertical. You do the trig
It moves 100 meters down and 250*4.52 meters horizontal.
again you do the trig