mathcalculus
posted by Shreya .
15+2yy^2/3y^216y+5
(5y)(3+y)/(3y1)(y5)
i factor out a negative one from (5y) to make it same like (y5)
(1)(5+y)(3+y)/(3y1)(y5)
i cancel off y5's. and i get
(1)(3+y)/(3y1)
but the real answer have to be 3+y/13y what i doing wrong?

Did you know that 3/4 = 3/4 = (3/4)
they are all the same
so look at your answer, which is correct
1(3+y)/(3y1)
= (3+y)/(1(3y1))
= (3+y)/(13y)
Sometimes it happens that you have an answer that looks different from the one in your text, but you may still be correct.
I would have marked your answer as correct to get full marks. 
oh wow i had not know that thanks so much Reiny for telling and explaining to me :)
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