If a projectial is fired at such an angle that the vertical componet of its velocity is 49m/s. The horizonal componet of its velocity is 61m/s, then how long will the projectia stay in the air? What distance will it travel? And what is the inital speed?
Your teacher is pretty easy.
vertical component: solve for time in air.
hf=ho+vyi*t- 4.9t^2 vyi=49, hf=ho=0
distance traveled:
distance= 61*timeinair
Initial speed= sqrt(49^2+61^1)