mathcalculus
posted by Shreya .
4x+3/2x12 = 6x+2/2x1
(4x+3)(2) = (6x+2)
8x6 = 6x+2
14x6 = 2
14x = 8
x = 4/7
i not think i did this right.

do you mean
[ (4x+3)/(2x1) ]  2 = (6x+2)/(2x1)
??????
If so please use parentheses so I can tell numerator from denominator.
If my guess is correct:
(4x+3) 2 (2x1) = 6x+2
4x + 3 4x + 2 = 6 x + 2
3 = 6 x
x = 1/2 
sorry yes you are right but don't all 2x1's cancel?

i think it supposed to be this
(4x+3)(2) = (6x+2) 
[ (4x+3)/(2x1) ]  2 = (6x+2)/(2x1)
Multiply everything, all terms both sides including 2, by (2x1)
[(4x+3)/(2x1)](2x1)2(2x1) = [(6x+2)/(2x1) ] (2x1)
You have to multiply that 2 by (2x1) so the (2x1) does not go away from the numerator when you clear it from the denominators.
so
(4x+3) 2 (2x1) = 6x + 2 
Perhaps your original line should read
[(4x+3)/(2x1)](2) = (6x+2)/(2x1)
if so then
2(4x+3) = 6x+2
8x  6 = 6x + 2
14 x = 8
x = 4/7
and your answer would be right 
thank you but in back of book it say no solution so i very confused.

If my solution of x = 1/2 is correct (and I think it is'
Then indeed the answer is NO SOLUTION
because
2x1 = 0 if x = 1/2
division by 0 
I did not notice that, should have.

thank you so much i not notice that either. thanks :)