x-1/x+1 = 2x/15

(15)(x-1) = (2x)(x+1)

2x^2-15x+17

do i put this in quadratic formula? i so confused.

First, get your simplification right:

(15)(x-1) = (2x)(x+1)
15x - 15 = 2x^2 + 2x
2x^2 - 13x + 15 = 0

You can use the quadratic formula, but it factors fairly easily:

(2x-3)(x-5) = 0

You can make it from there, I assume.

thanks very much steve i got it :)

To solve the equation 2x^2 - 15x + 17 = 0, you can indeed use the quadratic formula. Here's how you can apply it:

1. Identify the coefficients of the quadratic equation:
a = 2, b = -15, and c = 17.

2. Plug the values of a, b, and c into the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)

Substituting the values we have:

x = (15 ± √((-15)^2 - 4 * 2 * 17)) / (2*2)

3. Simplify the expression under the square root:
x = (15 ± √(225 - 136)) / 4
x = (15 ± √89) / 4

4. Apply the ± sign to obtain both possible solutions:
x1 = (15 + √89) / 4
x2 = (15 - √89) / 4

So the solutions to the quadratic equation 2x^2 - 15x + 17 = 0 are x1 = (15 + √89) / 4 and x2 = (15 - √89) / 4.