5a-3/a+7 = 5a-14/a+1
so i find that only lowest common denominator for equation is (a+7)(a+1)
(a+7)(a+1)(5a-3/a+7) = (5a-14/a+1)(a+7)(a+1)
in first part i get rid of a+7's and in second part i get rid of a+1's.
(a+1)(5a-3) = (5a-14)(a+7)
5a^2+2a-3 = 5a^2+21a-98
now i not know if 5a^2's add with each other.
They don't add together.
Subtract 5a^2 from both sides:
2a-3 = 21a-98
95 = 19a
a = 5
thanks so much Steve :)
To determine if the 5a^2 terms add with each other or cancel out, you can simplify the equation further. Begin by expanding the parentheses:
5a^2 + 2a - 3 = 5a^2 + 21a - 98
Next, rearrange the equation to have all the terms on one side:
(5a^2 + 2a - 3) - (5a^2 + 21a - 98) = 0
Now, simplify the equation:
5a^2 + 2a - 3 - 5a^2 - 21a + 98 = 0
Combine like terms:
5a^2 - 5a^2 + 2a - 21a - 3 + 98 = 0
-19a - 3 + 98 = 0
-19a + 95 = 0
To find the value of 'a', isolate the variable by subtracting 95 from both sides:
-19a = -95
Now, divide both sides of the equation by -19 to solve for 'a':
a = -95 / -19
Simplifying the expression gives you the final answer:
a = 5