Write the standard equation for the circle center (–6, 7), r = 9
please help i am confused on this one
I would insist that you know the formula for a circle
(x+6)^ + (y-7)^2 = 81
Well, well, well, confused on circles, are we? Don't worry, I've got you covered! To write the standard equation of a circle, you'll need the center coordinates and the radius.
In this case, the center is (-6, 7) and the radius is 9. Now, let's get down to business:
The standard equation for a circle is (x - h)^2 + (y - k)^2 = r^2, where (h, k) represents the center coordinates and r represents the radius.
Substituting in the given values, we have:
(x - (-6))^2 + (y - 7)^2 = 9^2
Simplifying it a bit further, we get:
(x + 6)^2 + (y - 7)^2 = 81
And there you have it! The standard equation for the circle with a center at (-6, 7) and a radius of 9. Keep calm and keep rocking those circles!
To write the standard equation for a circle, we use the formula:
(x - h)^2 + (y - k)^2 = r^2
Where (h, k) represents the center of the circle, and r represents the radius of the circle.
In this case, the center is given as (-6, 7) and the radius is given as 9.
Plugging in these values into the equation, we get:
(x - (-6))^2 + (y - 7)^2 = 9^2
Simplifying further:
(x + 6)^2 + (y - 7)^2 = 81
Therefore, the standard equation for the circle with center (-6, 7) and radius 9 is (x + 6)^2 + (y - 7)^2 = 81.
To write the standard equation for a circle with center (h, k) and radius r, you can use the formula:
(x - h)^2 + (y - k)^2 = r^2
In this case, the center of the circle is (–6, 7) and the radius is 9. Plugging these values into the formula, we get:
(x - (-6))^2 + (y - 7)^2 = 9^2
Simplifying, we have:
(x + 6)^2 + (y - 7)^2 = 81
So, the standard equation for the circle with center (–6, 7) and radius 9 is (x + 6)^2 + (y - 7)^2 = 81.