The perimeter of an isosceles triangle is 16 in. The area of the triangle is 12 sq in. If the base is x in, the height is 4 in and the legs are y in, find the length of the three sides.
A = x * h / 2 = 16 in ^ 2
16 = x * 4 / 2 Multiply both sides with 2
32 = 4 x Divide both sides with 4
8 = x
x = 8 in
P = x + 2 y = 16
16 = 8 + 2 y
16 - 8 = 2 y
8 = 2 y Divide both sides with 2
8 / 2 = y
4 = y
y = 4 in