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The perimeter of an isosceles triangle is 16 in. The area of the triangle is 12 sq in. If the base is x in, the height is 4 in and the legs are y in, find the length of the three sides.

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    A = x * h / 2 = 16 in ^ 2

    16 = x * 4 / 2 Multiply both sides with 2

    32 = 4 x Divide both sides with 4

    8 = x

    x = 8 in

    P = x + 2 y = 16

    16 = 8 + 2 y

    16 - 8 = 2 y

    8 = 2 y Divide both sides with 2

    8 / 2 = y

    4 = y

    y = 4 in

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