posted by Lexi .
You are at a furniture store and notice that a Grandfather clock has its time regulated by a physical pendulum that consists of a rod with a movable weight on it. When the weight is moved downward, the pendulum slows down; when it is moved upward, the pendulum swings faster. If the rod has a mass of 1.23 kg and a length of 1.25 m and the weight has a mass of 1.92 kg, where should the mass be placed to give the pendulum a period of 2.00 seconds? Measure the distance in meters from the top of the pendulum.
P= 2PI sqrt(L/g)
2.00=2PI sqrt(l/9.8) solve for L
but wouldn't the mass and the Length of the rod come in play?
Wouldn't the formula be T=2Pisqrt(I/mgd) where you solve for d, but my question iss do I add the two masses or am I over thinking this one