f(x)={2x-1 ifx>1
{-4 if -1¡Üx<1
{2-x^2 if x<1
State the value of f(0)and f(-2) and Graph
I will interpret you second function as
{ -4 if -1 ≤ x< 1
and to make any sense, the third function is probably
{2 - x^2 if x < -1
so f(0) = -4, (fits the second function)
f(-2) = 2 - 4 = -2
make a sketch of each graph on the same grid in pencil, then erase the part which is outside the domain.
The first is a straight line starting at (1,1) with an open circle at (1,1) and following y = 2x-1
the second is a horizontal line y = -4 from -1 to 1
closed circle at (-1,-4) and open circle at (1,-4)
third is a parabola which opens downwards and to the left of (-1, 1) with (-1,1) open circle.
To evaluate this function at a specific value of x, follow these steps:
1. Determine the value of x you want to evaluate the function at.
2. Check the given conditions and find the interval in which the value of x falls.
3. Apply the corresponding formula for that interval to calculate the value of f(x).
Let's work through an example. Suppose we want to evaluate f(x) at x = 0.
1. The value of x is given as 0.
2. Comparing 0 to the conditions, we find that -1 ≤ x < 1.
3. As x falls within the interval -1 ≤ x < 1, we use the formula f(x) = -4 for this interval.
Therefore, f(0) = -4.
So, f(0) = -4.
By following these steps, you can evaluate the function f(x) for any given value of x.